Question

Solve by completing square
method
√2f²-6f+3√2 =0​

Answer 1

Answer:

√2f2 - 6f + 3√2 = 0

Solution :

Comparing √2f2 - 6f + 3√2 = 0 and ax2 + bx + c = 0, we get

a = √2, b = -6 and c = 3√2

Then,

x = [-b ± √b2 - 4ac] / 2a

x = [-(-6) ± √(-6)2 - 4(√2)(3√2)] / 2(√2)

x = [6 ± √(36 - 24)] / 2√2

x = [6 ± √12] / 2√2

x = [6 ± 2√3] / 2√2

x = [6 + 2√3] / 2√2

x = 2(3 + √3) / 2√2

x = (3 + √3) / √2

x = [6 - 2√3] / 2√2

x = 2(3 - √3) / 2√2

x = (3 - √3) / √2

Therefore, the solution is {(3 + √3)/√2, (3 - √3)/√2}.