Question

solve by completing Square method 6y2 + y - 2 = 0​

Answer 1

answer is -2/3 or 1/2..

......

Answer 2

Step-by-step explanation:

6y2 + y - 2 = 0

12y + y - 2 = 0

13y - 2 = 0

BY Square method

13y - 2 = 0

$\sqrt{13x - 2 } = (a - b) {}^{2}$

BY Square

$13y - 2 = a {}^{2} - b {}^{2} \: + 2ab$

compare

$a {}^{2} - b {}^{2} = 13y$

2ab = -2

a= -1/b