solve by completing square method
Chandel1:
hi salonim
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x²-10x+5=0
x²-(2)(5)(x)+(5)²-(5)²+5=0
(x-5)²-25+5=0
(x-5)²=20
x-5=√20
x-5=+or- 2√5
x=2√5+5. x=5+2√5
x=√5(2+√5) x=√5(√5+2)
x²-(2)(5)(x)+(5)²-(5)²+5=0
(x-5)²-25+5=0
(x-5)²=20
x-5=√20
x-5=+or- 2√5
x=2√5+5. x=5+2√5
x=√5(2+√5) x=√5(√5+2)
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