Solve by completing squares
2x^[2} -5x +3 =0
plzz...fast.....
its urgent...
Answers
Answered by
1
Factorise it
It will become 2x^2-6x-x+3
2x(x-3)-1(x-3)
(2x-1)(x-3) Plz give brainliest to me if answer is helpful
It will become 2x^2-6x-x+3
2x(x-3)-1(x-3)
(2x-1)(x-3) Plz give brainliest to me if answer is helpful
PoojaNair:
Sry ..i need the answer to be solved by completing square method
Answered by
8
Hey here is your answer!!!☺️
==========================
✔✔Factorise.....
2x² - 5x + 3
2x² - 2x - 3x + 3
2x(x - 1) - 3(x - 1)
(2x - 3)(x - 1)
========================
I HOPE IT WILL HELP YOU ☺️✌️
Thank you ✌️
==========================
✔✔Factorise.....
2x² - 5x + 3
2x² - 2x - 3x + 3
2x(x - 1) - 3(x - 1)
(2x - 3)(x - 1)
========================
I HOPE IT WILL HELP YOU ☺️✌️
Thank you ✌️
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