Math, asked by jettx98, 1 year ago

Solve by completing the square: 5x^2+20x+32=0
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Answers

Answered by fidauzair
3

5[x²+(2)²—(2)²]+32

5[(x+2)²—4]+32

5(x+2)²—20+32

5(x+2)²+12

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