Solve by completing the square 6x2-13x-5=0
Answers
Answered by
18
6x2-13x-5=0
Two solutions were found :
x = -1/3 = -0.333
x = 5/2 = 2.500
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((2•3x2) - 13x) - 5 = 0
Step 2 :
Two solutions were found :
x = -1/3 = -0.333
x = 5/2 = 2.500
Step by step solution :
Step 1 :
Equation at the end of step 1 :
((2•3x2) - 13x) - 5 = 0
Step 2 :
Answered by
9
Factor 6x^2 - 13x + 5 = 0?
11 answers · Mathematics
Best Answer
SOLUTION: (3x -5)(2x -1) = 0
EXPLANATION:
First notice the highest term coefficient. it is 6.
That means it can be either
(2x+___)(3x+___) //* or could be negative sign
or
(x+____)(6x+___)
Those would make highest term 6x^2.
Now focus on constant 5.
It can be
(2x__1)(3x___5)
Where ___ indicates you have to do trial and error for sign.
To get positive 5, it can be either both signs are positive or both are negative. But now look at the middle terms. It is -13
So in order to get -13, you need both negative signs because the middle term in binomial is where outside product and inside product in nested form gets added in FOIL method.
So it should be (3x -5 )(2x-1)
The more you practice, you will be able to do it in your head. Otherwise you need to do many trials and errors.
Now in case you have to solve for x, it should be obvious that 3x-5 = 0 and 2x -1 = 0
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