solve by completing the square method .
3x^2+7x+2 = 0
for class 10 cbse board.
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3x^2+6x+1x+2
3x(x+2)+1(x+2)
(x+2)(3x+1)
x=-2&-1/3
3x(x+2)+1(x+2)
(x+2)(3x+1)
x=-2&-1/3
Answered by
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3x²+7x+2=0
3x²+(6x+x)+2=0
3x²+6x+x+2=0
3x(x+2)+1(x+2)
(x+2)(3x+1)
3x²+7x+2=0
x²+7x/3+2/3=0
x²+7x/3=-2/3
x²+7x/3+(7/3)²=(7/3)²-2/3
(x+7/3)²=49/9-2/3
(x+7/3)²=49-6/9
(x+7/3)²=43/9
(x+7/3)=root43/3
x=root43/3-7/3
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