Question

Solve by completing the square method=
4x^2+4√3x+3​

Answer 1

Answer:

I hope it helpful.......

Answer 2

Answer:

$↪x = - \frac{ \sqrt{3} }{2} and \: x = - \frac{ \sqrt{3} }{2}$

✵Step by step explanation

$↪given \: equation \: is \: {4x}^{2} + 4 \sqrt{3} x + 3 = 0 \\↪ on \: dividing \: both \: sides \: by \: 4 \: we \: get \\ ↪ {x}^{2} + \sqrt{3} x + \frac{3}{4} = 0 \\↪ {x}^{2} + \sqrt{3x} = - \frac{3}{4} \\ ↪on \: adding \: ({ \frac{1}{2} \: coefficient \: of \: x})^{2} \\ ↪i.e. \\↪ ({ \frac{1}{2} \sqrt{3} })^{2} = \frac{3}{4} both \: sides \: we \: get \\ ↪{x}^{2} + \sqrt{3} x + \frac{3}{4} = - \frac{3}{4} + \frac{3}{4} \\ ↪( {x + \frac{ \sqrt{3} }{2} )}^{2} = 0$

$↪on \: taking \: sqr.root \: both \: sides \: we \: get \\↪ x + \frac{3}{2} = 0 \: and \: x + \frac{ \sqrt{3} }{2} = 0 \\ ↪x = - \frac{ \sqrt{3} }{2} and \: x = - \frac{ \sqrt{3} }{2} \\ ↪ \: hence \: roots \: of \: equation \: are \\ \: ↪x = - \frac{ \sqrt{3} }{2} and \: x = - \frac{ \sqrt{3} }{2}$

Original answer☑