solve by completing the square of x^2 - 10r =12
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Hey buddy here is your answer
x^2 - 10r =12
=>x^2-10r-12 = 0
Hence the value of roots are [-b±√b^2-4ac]/2a
=[10±√100-4(1)(-12)]/2(1)
=[10±√100+48]/2
=[10±√148]/2
=[10±2√37]/2
=5±√37
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Answered by
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Answer:tgty
Step-by-step explanation:
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