Math, asked by UchihaItachi123, 23 hours ago

solve by cramer rule x=y=z=-1,x+2z+2z=-4,x+3y+yz=-6

Answers

Answered by umeshwarkad1983
0

Answer:

Correct option is

D

x=

7

24

,y=

7

20

,z=0

Given equation are

2x−y+2z=4

3x+2y+3z=16

x+3y+2z=12

Δ=

2

3

1

−1

2

3

2

3

2

=2(4−9)+1(6−3)+2(9−2)

=−10+3+14=7

Δ

x

=

4

16

12

−1

2

3

2

3

2

=4(4−9)+1(32−36)+2(48−24)

=−20−4+48=24

Δ

y

=

2

3

1

4

16

12

2

3

2

=2(32−36)−4(6−3)+2(36−16)

=−8−12+40=20

Δ

z

=

2

3

1

−1

2

3

4

16

12

=2(24−36)+1(36−16)+4(9−2)

=−48+20+28=0

∴x=

Δ

Δ

x

,y=

Δ

Δ

y

,z=

Δ

Δ

z

⟹x=

7

24

,y=

7

20

,z=0

Similar questions