Question

solve by cramer's rule 3x+2y+6z=1 2x-3y+4z=3 4x-3y+7z=4


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Answer 1

Answer:

(3x+2y+6z=1)×2

(2x-3y+4z=3)×3

6x+4y+12z=2

6x-9y+12z=9

subtract equation 1-2

13y=-7

y=-7/13

(3x-14/13+6z=1)×4

(4x+21/13+7z=4)×3

12x-56/13+24z=4

12x+63/13+21z=12

equation 2-1

119/13-3z=8

15/13=3z

z=5/13

3x+2y+6z=1

3x-14/13+30/13=1

3x-16/13-1

3x-29/13

3x=29/13

x=29/39