solve by cross multiplication. 4x-3y = 8 ; x-2y =-3
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Given:- 4x-3y = 8 and x-2y = -3
from 2nd equation, we get
x = 2y-3
Substituting the value of x in equation1, we get
4(2y-3) -3y = 8 ⇒ 8y-12 - 3y = 8 ⇒ 5y = 8+12 = 20 ⇒ y = 20/5 = 4
Substituting the value of y in 3rd equation, we get
x = 2*4 - 3 = 8 - 3 = 5
Ans: x=5, y=4
from 2nd equation, we get
x = 2y-3
Substituting the value of x in equation1, we get
4(2y-3) -3y = 8 ⇒ 8y-12 - 3y = 8 ⇒ 5y = 8+12 = 20 ⇒ y = 20/5 = 4
Substituting the value of y in 3rd equation, we get
x = 2*4 - 3 = 8 - 3 = 5
Ans: x=5, y=4
yash307:
thanks
can u solve one more questio
by cross multlipication it is wrong
Oh sorry, my mistake, i did it by Substitution method. Post your question again, I ll do it it in required method.
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Answered by
2
Answer:
Given:- 4x-3y = 8 and x-2y = -3
from 2nd equation, we get
x = 2y-3
Substituting the value of x in equation1, we get
4(2y-3) -3y = 8 ⇒ 8y-12 - 3y = 8 ⇒ 5y = 8+12 = 20 ⇒ y = 20/5 = 4
Substituting the value of y in 3rd equation, we get
x = 2*4 - 3 = 8 - 3 = 5
Ans: x=5, y=4
Step-by-step explanation:
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