Solve by cross-multiplication method :
2 3 3 1 5; 9 0
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Answer:
Step-by-step explanation:
To solve the equations in a simplified way, we use following table:
Method of Cross Multiplication
xB1C2−B2C1=yC1A2−C2A1=1A1B2−A2B1
Equating one another we find the value of x and y of the given equations.
Let us solve some examples based upon this concept:
1. Solve for ‘x’ and ‘y’:
3x + 2y + 10 = 0, and
4x + 5y + 20 = 0.
Answered by
0
To solve the equations in a simplified way, we use following table:
Method of Cross Multiplication
xB1C2−B2C1=yC1A2−C2A1=1A1B2−A2B1
Equating one another we find the value of x and y of the given equations.
Let us solve some examples based upon this concept:
1. Solve for ‘x’ and ‘y’:
3x + 2y + 10 = 0, and
4x + 5y + 20 = 0.
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