solve by cross multiplication method 2(ax-by)+(a+4b)=0 2(bx+ay)+(b-4a)=0
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Step-by-step explanation:
2(ax-by)+(a+4b)= 0 eqn1
2(bx+ay)+(b-4a)= 0 eqn2
Multiplying eqn1 and 2
we get,
=4(ax-by)(bx+ay) + (a+4b)(b-4a)
=(ax-by) (bx+ay) + (a+4b) + b
=by+bx+(a+5b)
=2xy+(a+5b)
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