Math, asked by jayesh2611, 1 year ago

solve by cross multiplication method 2(ax-by)+(a+4b)=0 2(bx+ay)+(b-4a)=0​

Answers

Answered by DevMazumdar
6

Step-by-step explanation:

2(ax-by)+(a+4b)= 0 eqn1

2(bx+ay)+(b-4a)= 0 eqn2

Multiplying eqn1 and 2

we get,

=4(ax-by)(bx+ay) + (a+4b)(b-4a)

=(ax-by) (bx+ay) + (a+4b) + b

=by+bx+(a+5b)

=2xy+(a+5b)

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