Solve by cross multiplication method 2x=5y+4, 3x-2y+16=0
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equations
2x-5y-4=0
3x-2y+16=0
by cross-multiplication
x/b1c2-b2c1 = y/c1a2-c2a1 = 1/a1b2-a2b1
x/-80-8 = y/-12-32 = 1/-4+15
x/-88 = y/-44 = 1/11
Therefore
1/11 = x/-88
x=-8
1/11=y/-44
y=-4
2x-5y-4=0
3x-2y+16=0
by cross-multiplication
x/b1c2-b2c1 = y/c1a2-c2a1 = 1/a1b2-a2b1
x/-80-8 = y/-12-32 = 1/-4+15
x/-88 = y/-44 = 1/11
Therefore
1/11 = x/-88
x=-8
1/11=y/-44
y=-4
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Cute786
Secondary School Math 5+3 pts
Solve by cross multiplication method 2x=5y+4, 3x-2y+16=0
by Nekazoya 21.05.2018
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equations
2x-5y-4=0
3x-2y+16=0
by cross-multiplication
x/b1c2-b2c1 = y/c1a2-c2a1 = 1/a1b2-a2b1
x/-80-8 = y/-12-32 = 1/-4+15
x/-88 = y/-44 = 1/11
Therefore
1/11 = x/-88
x=-8
1/11=y/-44
y=-4
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