solve by cross multiplication method 3x-5y-4=0. and 9x-2y-7=0
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3x-5y-4=0......(1)
9x-2y-7=0......(2)
from equation (1),we get
A1=3,B1=-5,C1=-4
from equation (2),we get
A2=9,B2=-2,C2=-7
By cross multiplication,we have
X/B1C2-B2C1=Y/C1A2-C2A1=1/A1B2-A2B1
X/-5×-7-(-2)×(-4)=Y/-4×9-(-7)×3=1/3×(-2)-9×(-5)
X/27=Y/-15=1/39
X/27=1/39 Y/-15=1/39
X=9/13 Y=-5/13
9x-2y-7=0......(2)
from equation (1),we get
A1=3,B1=-5,C1=-4
from equation (2),we get
A2=9,B2=-2,C2=-7
By cross multiplication,we have
X/B1C2-B2C1=Y/C1A2-C2A1=1/A1B2-A2B1
X/-5×-7-(-2)×(-4)=Y/-4×9-(-7)×3=1/3×(-2)-9×(-5)
X/27=Y/-15=1/39
X/27=1/39 Y/-15=1/39
X=9/13 Y=-5/13
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