Solve by cross multiplication method
4x+3y=17; 3x-4y+6=0
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hi dear
given equations are 4x+3y=17 and 3x−4y+6=0
Comparing with a1x+b1y+c1=0 and a2x+b2y+c2=0 we have
a1=4,b1=3,c1=−17 and a2=3,b2=−4,c2=6
Now , x=a1b2−a2b1b1c2−b2c1 and y=a1b2−a2b1c1a2−c2a
hopes its helps you
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