solve by cross multiplication method X /3+Y/4=11 and 5X/6-Y/3=-7
Answers
Answered by
7
⭐️⭐️⭐️your answer⭐️⭐️⭐️
x/3 + y/4 = 11
4x + 3y = 132
3y = 132 - 4x
y = (132 - 4x)/3
5x/6 - y/3= -7
5x - 2y = -42
5x - 2[(132-4x)/3] = -42
5x - (264 - 8x)/3 = -42
15x - 264 +8x = -126
23x = 264 - 126
x = 138/23
x = 6
y = (132 - 4x)/3
y = (132 - 24)/3
y = 108/3
y = 36
x/3 + y/4 = 11
4x + 3y = 132
3y = 132 - 4x
y = (132 - 4x)/3
5x/6 - y/3= -7
5x - 2y = -42
5x - 2[(132-4x)/3] = -42
5x - (264 - 8x)/3 = -42
15x - 264 +8x = -126
23x = 264 - 126
x = 138/23
x = 6
y = (132 - 4x)/3
y = (132 - 24)/3
y = 108/3
y = 36
bhumikapatil:
u only do
Answered by
0
Step-by-step explanation:
Here is your answer
Hope it helps you
Attachments:
Similar questions