Question

solve by cross multiplication method x-3y-7=0 ,3x-3y-15=0​

Answer 1

Explanation:

$x - 3y - 7 = 0 = > x - 3y = 7$

$3x - 3y = 15 = 0 = > 3x - 3y = 15$

$= > x - y = 5$

Subtract 1st equation from 2nd equation, we get

$x - y - (x - 3y) = 5 - 7 = > 2y =$

$- 2 = > y = - 1$

Substitute y => -1 in Equation 1 => x -3(-1) = 7 => x+3=7 => x=4. x=4 and y =-1 is the solution of the system of linear equations

Answer 2

This is answer where x=4 ,y=-1