solve by determinant method 6x_3y=_3, 4x+5y=_9
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6x-3=3....(1)
4x+5y=9.... (2)
D=|6 -3|
|4 5|
=5×6-(-3)×4
=42
Dx=|-3 3|
|5 9|
-3×9-3×5
=-27-15
=-42
Dy=|6 3|
|4 9|
=9×6-3×4
=54-12
=42
x=Dx/D
=-42/42
=-1
y=Dy/D
=42/42
=1
hope it will help you it is in cramer's rule also called as determinant method.
4x+5y=9.... (2)
D=|6 -3|
|4 5|
=5×6-(-3)×4
=42
Dx=|-3 3|
|5 9|
-3×9-3×5
=-27-15
=-42
Dy=|6 3|
|4 9|
=9×6-3×4
=54-12
=42
x=Dx/D
=-42/42
=-1
y=Dy/D
=42/42
=1
hope it will help you it is in cramer's rule also called as determinant method.
CharlesPonney:
let me try to analyse it
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