Question

solve by distance formula
p (1,2),q (2,8/5),r (3,6/5)
​

Answer 1

Step-by-step explanation:

Let the Points P(1, 2) ,Q(2,8/5 ) , R(3,6/5) be P(x₁, y₁), Q(x₂,y₂), R(x₃,y₃).

Let us first find the Slope of PQ,

∵ m = \frac{y_2 - y_1}{x_2 - x_1}

x

2

−x

1

y

2

−y

1

∴ m = (8/5 - 2)/(2 - 1)

= -1/1

= -1

Now For th Slope of QR,

m = \frac{y_3 - y_2}{x_3 - x_2}

x

3

−x

2

y

3

−y

2

= (6/5 - 8/5)/(3 - 2)

= (-2/5)/1

= -2/5

Since, the Slope of both the lines PQ and QR are not same therefore, Points are non-Collinear.

hope if it's correct