Math, asked by pallavidevadiga08, 11 months ago

Solve by elemination method x-3y = 10 and x - 7y= -30

Answers

Answered by rohit222255
8

Step-by-step explanation:

×-3y=10

×-7y=-30

- + +

4y=40

y=10

×-3×10=10

×=40

Answered by Anonymous
13

\underline{\underline{\mathfrak{\green{Answer:-}}}}

x = 40

y = 10

\underline{\underline{\mathfrak{\green{Explanation:-}}}}

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Given:

Pair of linear equations are-

x-3y = 10 and x-7y = -30

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To Find:

values of x and y

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Solution:

Let,

\mathsf{x-3y = 10 -------(1) }

\mathsf{x-7y = -30 -------(2)}

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Now, eq.(1) - (2)

\mathsf{(x-3y)-(x-7y) = 10-(-30)}

\mathsf{x-3y-x+7y = 10+30}

\mathsf{4y = 40}

\mathsf{y = \dfrac{40}{4}}

\mathsf{y = 10}

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By sub. value of "y" in eq.(1)

\mathsf{x-3(10) = 10}

\mathsf{x-30= 10}

\mathsf{x = 10+30}

\mathsf{x = 40}

_____________________

\underline{\underline{\mathfrak{\red{Verification:-}}}}

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Let us substitue the values of 'x' and 'y' in eq.(1)

\mathsf{x-3y = 10}

\mathsf{40-3(10) = 10}

\mathsf{40-30 = 10}

\mathsf{10= 10}

Now, substitue the values of 'x' and 'y' in eq.(2)

\mathsf{x-</strong><strong>7</strong><strong>y</strong><strong> = </strong><strong>-</strong><strong>3</strong><strong>0</strong><strong>}

\mathsf{40-7(10) = -30}

\mathsf{40-70 = -30}

\mathsf{-30 = -30}

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Hence, the values of 'x' and 'y' are 40 and 10 respectively!


Anonymous: ✌✌best
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