Math, asked by yg3209985, 1 month ago

Solve by Eliminatin 2x+3y=46 & 3x+5y = 74​

Answers

Answered by Aditi12809
1

Answer:

Step-by-step explanation:Given pair of linear equations is 2x + 3y = 46 …(i)

And 3x + 5y = 74 …(ii)

On multiplying Eq. (i) by 3 and Eq. (ii) by 2 to make the coefficients of x equal, we get the equation as

6x + 9y = 138 …(iii) 6x + 10y = 148 …(iv)

On subtracting Eq. (iii) from Eq. (iv),

we get 6x + 10y – 6x – 9y = 148 – 138 ⇒ y = 10

On putting y = 10 in Eq. (ii),

we get 3x + 5y = 74 ⇒ 3x + 5(10) = 74 ⇒ 3x + 50 = 74 ⇒ 3x = 74 – 50 ⇒ 3x = 24 ⇒ x = 8

Hence, x = 8 and y = 10 , which is the required solution.

Answered by shikhabagri1983
0

Answer:

2x + 3x + 3y + 5y = 46 + 74

5x + 8y = 120

x + 8y = 120/5

x + y = 24/8

x + y = 3

Step-by-step explanation:

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