Solve by Eliminatin 2x+3y=46 & 3x+5y = 74
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Answered by
1
Answer:
Step-by-step explanation:Given pair of linear equations is 2x + 3y = 46 …(i)
And 3x + 5y = 74 …(ii)
On multiplying Eq. (i) by 3 and Eq. (ii) by 2 to make the coefficients of x equal, we get the equation as
6x + 9y = 138 …(iii) 6x + 10y = 148 …(iv)
On subtracting Eq. (iii) from Eq. (iv),
we get 6x + 10y – 6x – 9y = 148 – 138 ⇒ y = 10
On putting y = 10 in Eq. (ii),
we get 3x + 5y = 74 ⇒ 3x + 5(10) = 74 ⇒ 3x + 50 = 74 ⇒ 3x = 74 – 50 ⇒ 3x = 24 ⇒ x = 8
Hence, x = 8 and y = 10 , which is the required solution.
Answered by
0
Answer:
2x + 3x + 3y + 5y = 46 + 74
5x + 8y = 120
x + 8y = 120/5
x + y = 24/8
x + y = 3
Step-by-step explanation:
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