Question

Solve by Eliminating :
23x + 17y = 6; 39x – 19y = 58
15 points
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Answer 1

Answer:

x = 1

y = 1

Step-by-step explanation:

Take L.C.M of 17 and 19 = 323

19(23x+17y)=6*19

17(39x-19y)=58*17

437x + 323y = 114

663x - 323 y = 986

1100x=1100

x = 1

23x + 17y = 6

17y = 6-23x

y = 6-23x/17

y == 6-23/17

y = 17/17

y = 1

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Answer 2

Answer:

x = 1

y = -1

Step-by-step explanation:

23x + 17y = 6 ----------(i)

39x - 19y = 58 --------(ii)

Multiply eq.(i) by 19 and eq. (ii) by -17

23x + 17y = 6

19(23x + 17y) = 19(6)

437x + 323y = 114 ---------(iii)

39x - 19y = 58

-17(39x - 19y) = -17(58)

-663x + 323y = -986 ---------(iv)

Sub eq. (iii) from eq.(iv)

-663x + 323y +986 -(437x + 323y - 114) = 0

-663x + 323y + 986 - 437x - 323y + 114 = 0

-1100x + 1100 =0

-1100x = -1100

x = 1

Put x = 1 in eq.(iii)

437x + 323y = 114

437(1) + 323y = 114

437 + 323y = 114

323y = 114 - 437

323y = -323

y = -1