Question

solve by eliminating or substitution method​

Answer 1

Answer:

4x+6/y=15

let 1/y be b

4x+6b=15---(1)

3x -4b=7---(2)

value of x from eqn 2,x=7+4b/3

substitute in eqn (1)

4(7+4b/3)+6b=15

28+16b/3=15 (lcm=3)

28+16b=45

16b=17

b=17/16

put b im eqn (2)

3x-4(17/16)=7

48x-68=112

x=180/48=3.7f

y=16/17

Answer 2

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