Math, asked by Dhanikaaviya07, 3 months ago

Solve by elimination 2x+5y+2z =-38
3x-2y+4z=17
-6x+y-7z=-12​

Answers

Answered by MrFire600
0

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⇨3x - 2y + 4z = 17

⇨3x - 2y + 4z - ( - 2y + 4z) = 17 - (2y + 4z)

⇨3x = 17 + 2y - 4z

 ⇨\frac{3x}{3} =  \frac{17}{3} +  \frac{2y}{3} -  \frac{4z}{3}

⇨x =  \frac{17 \times 2y - 4z}{3}

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Answered by amarjyotijyoti87
1

Answer:

3x−2y+4z=17

⇨3x - 2y + 4z - ( - 2y + 4z) = 17 - (2y + 4z)⇨3x−2y+4z−(−2y+4z)=17−(2y+4z)

⇨3x = 17 + 2y - 4z⇨3x=17+2y−4z

⇨\frac{3x}{3} = \frac{17}{3} + \frac{2y}{3} - \frac{4z}{3}⇨33x=317+32y−34z

⇨x = \frac{17 \times 2y - 4z}{3}⇨x=317×2y−4z

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