Solve by elimination. 3x-2y=5 and 2x+3y =1
Answers
Answer:
Please check your question once....it must be
3x+2y=5
2x-3y=7
Step-by-step explanation:
3x + 2y = 5 ...... (1)
2x - 3y = 7 ....... (2)
We multiply eq (1) with 2 and eq (2) with 3
eq (1) x 2 => 6x + 4y = 10 ...... (3)
eq (2) x 3 => 6x - 9y = 21 ...... (4)
eq (3) - eq (4) by elimination method
6x + 4y - 6x + 9y = 10 - 21
13y = -11
y = -11/13
substitute the value of y in any of the equation to get the value of x
{ I'm substituting it in eq (1) }
3x + 2(-11/13) = 5
3x - 22/13 = 5
3x = 5 + 22/13
3x = 87/13
x = 87/39
x = 29/13
Hope this helps ✌️☺️✌️
Answer:
Please check your question once....it must be
3x+2y=5
2x-3y=7
Step-by-step explanation:
3x + 2y = 5 ...... (1)
2x - 3y = 7 ....... (2)
We multiply eq (1) with 2 and eq (2) with 3
eq (1) x 2 => 6x + 4y = 10 ...... (3)
eq (2) x 3 => 6x - 9y = 21 ...... (4)
eq (3) - eq (4) by elimination method
6x + 4y - 6x + 9y = 10 - 21
13y = -11
y = -11/13
substitute the value of y in any of the equation to get the value of x
{ I'm substituting it in eq (1) }
3x + 2(-11/13) = 5
3x - 22/13 = 5
3x = 5 + 22/13
3x = 87/13
x = 87/39
x = 29/13
Hope this helps ✌️☺️✌️
Step-by-step explanation:
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