Question

solve by elimination 3x-5y 9x-2y=7


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Answer 1

Answer:

Given

3x - 5y - 4 = 0

→ 3x - 5y = 4..............( i )

And, 9x = 2y + 7

→ 9x - 2y = 7.................( ii )

Now, by multiplying with 3 on both sides in first equation, we get

3(3x - 5y) = 3(4)

→ 9x - 15y = 12............ (iii)

Now, Subtract equation (ii) from equation (iii)

→ 9x - 15y - (9x - 2y) = 12 - 7

→ 9x - 15y - 9x + 2y = 5

→ -13y = 5

→ y = -5/13

Substitute the value of y to get the value of x.

9x = 2y + 7

→ 9x = -10/13 + 7

(as, y = -5/13, → 2y = -10/13)

→ 9x = (-10 + 91)/13

(after taking LCM ↑)

→ 9x = 81/13

→ x = 9/13

\sf Substitution \ Method

Given 9x = 2y + 7

→ x = (2y + 7)/9

And, 3x - 5y - 4 = 0

So, substitute the value of x in terms of y in second equation

→ 3(2y + 7)/9 - 5y - 4 = 0

→ (2y + 7)/3 - 5y - 4 = 0

(cancelling 9 in the denominator by 3)

→ (2y + 7 - 15y)/3 - 4 = 0

(by taking LCM)

→ (7 - 13y)/3 = 4

→ 7 - 13y = 3(4)

→ 7 - 13y = 12

→ - 13y = 5

→ y = -5/13

Again, by putting the value of y, we will get the value of x.

Hence,

\huge\mathfrak{Answer}

\huge{x = \frac{9}{13}}

\huge{y = \frac{-5}{13}}

Answer 2

Answer:

$\huge\orange{x = \frac{9}{13}}$

$\huge\orange{y = \frac{ - 5}{13}}$

Step-by-step explanation:

According to the Q,

$>> 3x - 5y = 4 -----(1)$

$>> 9x - 2y = 7 -----(2)$

(1) x 3:

$>> 3(3x - 5y) = 4 * 3$

$>> 9x - 15y = 12 -----(3)$

(3) - (2):

$>> (-15y) - (-2y) = 12 - 7$

$>> (-15y) + 2y = 5$

$>> (-13y) = 5$

$\orange{ > > y = \frac{ - 5}{13}}$

Subsistute the Value of "y" in -----(1)

$>> 3x - [(5 * -5)/13] = 4$

$>> 3x - [-25/13] = 4$

$>> 3x + (25/13) = 4$

$>> 3x = 4 - (25/13)$

$>> 3x = (52 - 25)/13$

$>> x = (52 - 25)/(13 * 3)$

$>> x = 27/39$

$\orange{ > > x = \frac{9}{13}}$

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