Math, asked by turiabhishak, 7 months ago

Solve by elimination 5/ (x-1) + 1/(y-2)=2
and 6/(x-1)-3/(Y-2)
=1​

Answers

Answered by deveshupadhyay277304
0

Answer:

let =1/(x-1)=M

1/(y-2)=N

Step-by-step explanation:

5m+1n=2 ...eq(i)

6m-3n=1...eq(ii)

multiply equation 1 by 6 and equation ii by 5

equations will subtracted ,if sign of same variables are same

30m-15n=5

30m+6n=12

-. -. -

____________

-21n=-7

21n=7

n=7/21=1/3

but we know that n=1/(y-2)

1/(y-2)=1/3

Y-2=3

y=3+2

y=5

and for m

put the value of n in eq I

5m+1/3=2

5m=2-1/3

5m=(6-1)/3

5m=5/3

m=1/3

but we know that m=1/x-1

1/(x-1)=1/3

after cross multiply,we get

x-1=3

x=3+1

x=4

Answered by iamDivya
0

maths class 10 chapter 3 exercise 3.6

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