Solve by elimination 5/ (x-1) + 1/(y-2)=2
and 6/(x-1)-3/(Y-2)
=1
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Answer:
let =1/(x-1)=M
1/(y-2)=N
Step-by-step explanation:
5m+1n=2 ...eq(i)
6m-3n=1...eq(ii)
multiply equation 1 by 6 and equation ii by 5
equations will subtracted ,if sign of same variables are same
30m-15n=5
30m+6n=12
-. -. -
____________
-21n=-7
21n=7
n=7/21=1/3
but we know that n=1/(y-2)
1/(y-2)=1/3
Y-2=3
y=3+2
y=5
and for m
put the value of n in eq I
5m+1/3=2
5m=2-1/3
5m=(6-1)/3
5m=5/3
m=1/3
but we know that m=1/x-1
1/(x-1)=1/3
after cross multiply,we get
x-1=3
x=3+1
x=4
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maths class 10 chapter 3 exercise 3.6
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