Question

Solve by ' Elimination by equating Coefficients' method

$2.) \: \: \frac{x}{a} - \frac{y}{b} = 0$

;

$ax + by = a {}^{2} + b {}^{2}$
Class 10


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Answer 1

(2)

= > (x/a) - (y/b) = 0

bx - ay = 0 ---------- (1)

ax + by = a^2 + b^2 ------- (2).

On solving (1) * a, (2) * b, we get

= > abx - a^2y = 0

= > abx + b^2y = a^2b + b^3

-------------------------------------

-(a^2 + b^2)y = -(a^2b + b^3)

(a^2 + b^2)y = b(a^2 + b^2)

y = b.

Substitute y = b in (1), we get

= > bx - ay = 0

= > bx - a(b) = 0

= > bx - ab = 0

= > bx = ab

= > x = ab/b

= > x = a.

Therefore the value of x = a and y = b.

Hope this helps!

Answer 2

Solving the above equation with substitution method....
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