solve by elimination method. 1. x+2y+1=0 and 2x-3y-12=0
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Given:-
•eq-(1)→x+2y+1=0
•eq-(2)→2x-3y-12=0
To find:-
The value of x and y?
♦Answer:-
*Multiply eq-(1) by 2*
We get,
→2x+4y+2=0-(3)
Now,
*Add Eq-(3)&(2)*
•Refer Attachment for addition•
we get, y=2-(4)
•Using eq-(4) in eq-(1) or eq(2)•
*I prefer using in eq-(1)*
→x+2×2=-1
→x=-1-4
→x=-5
★x=-5★
and
★y=2★
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