solve by elimination method 2(3x-y)=5xy ; 2(x+4y)=5xy
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Step-by-step explanation:
The given equations are:
2(3x-y)=5xy and 2(x+3y)=5xy, thus on solving, we get
6x-2y=5xy (1)
2x+6y=5xy (2)
Multiply equation (1) with 2 and (2) with 6 and then subtracting, we get
12x-4y-12x-36y=10xy-30xy
-40y=-20xy
x=2
Substitute the value of x=2 in equation (1),.we get
6(2)-2y=5(2)y
12-2y=10y
12=12y
y=1
Thus, x=2 and y=1
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