Math, asked by avabb, 9 months ago

Solve by elimination method :2x +3y =4;3x - 2y = 6

Answers

Answered by laramieteeves
7

Answer:

2x +3y =4----- (1)

3x - 2y = 6 -----(2)

Multiplying eq 1 by 3 and eq 2 by 2

6x+9y-12=0 ----(3)

6x-4y-12=0 ----(4)

Subtracting eq 4 from eq 3

6x+9y-12-6x+4y+12=0

5y=0

y=0

Substituting the value of y in eq 1

2x +3(0) =4

2x=4

x=2

Value of x=2 and y=0

Hope it helps<3

Answered by vidhic324
0

Answer:

x = 2, y = 0

Step-by-step explanation:

2x + 3y = 4 ... I

3x - 2y = 6 .....II

First we need to choose a variable. You can choose any, but it's better to choose y, as y has opposite signs in both equations, so we can simply add them

Now make the coefficients of the chosen variable same.

Multiply eqn. I by 2 and eqn. II by 3

2(2x + 3y = 4) => 4x + 6y = 8... III

3(3x - 2y = 6) => 9x - 6y = 18 ... IV

Add eqn. III and IV

On adding, 6y and -6y get cancelled, and we get

4x + 9x = 8 + 18

13x = 26

x = 2

Substitute x = 2 in eqn. I

2(2) + 3y = 4

4 + 3y = 4

3y = 0

y = 0

Solution set = {2, 0}

Hope this helps!

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