Question

solve by elimination method 2x+3y=4 and x-y+3=0​

Answer 1

Answer:

BY USING ELIMINATION METHOD

2x + 3y = 4 ..............(i)

x - y = -3 ............(ii) (Transposing 3 towards RHS)

Multiplying eq (ii) by 2 we get 2x - 2y = -6

let's say this is eq number

eq( i) from (iii)

2x + 3y = 4

2x - 2y = -6

- + +

-------------------

0x + 5y = 10

-------------------

5y = 10 therefore y =2

Putting value of y in eq (i) we get 2x + 3(2) =4

2x + 6 = 4

2x = -2

x = -1

Therefore, value of x = -1 and y = 2

HAVE A COOL DAY

Answer 2

The value of x and y are -1 and 2 respectively.

Given:

2x+3y=4 and x-y+3=0​

To Find:

To solve the given equations by using the elimination method.

Solution:

Let 2x+3y = 4 -------------(1)

x-y+3 = 0 --------------------(2)

Multiply equation (2) by 3.

⇒ 3x-3y+9 =0 ---------------(3)

Add equation (1) and equation (3)

2x+3y+3x-3y +9= 4

5x+9=4

5x=4-9

5x =-5

x=-1

Put x=-1  in Equation (1)

2(-1) +3y = 4

-2+3y =4

3y=4+2

3y = 6

y = 2

Therefore, x= -1 and y =2.

#SPJ2

Learn More

1) Solve x +y=5 And 2x-3y=4 using elimination method

Link:https://brainly.in/question/4005985

2) Using elimination method,4x-3y=8,18x-3y=29

Link:https://brainly.in/question/10449110