solve by elimination method 2x+3y=4 and x-y+3=0
Answers
Answer:
BY USING ELIMINATION METHOD
2x + 3y = 4 ..............(i)
x - y = -3 ............(ii) (Transposing 3 towards RHS)
Multiplying eq (ii) by 2 we get 2x - 2y = -6
let's say this is eq number
eq( i) from (iii)
2x + 3y = 4
2x - 2y = -6
- + +
-------------------
0x + 5y = 10
-------------------
5y = 10 therefore y =2
Putting value of y in eq (i) we get 2x + 3(2) =4
2x + 6 = 4
2x = -2
x = -1
Therefore, value of x = -1 and y = 2
HAVE A COOL DAY
The value of x and y are -1 and 2 respectively.
Given:
2x+3y=4 and x-y+3=0
To Find:
To solve the given equations by using the elimination method.
Solution:
Let 2x+3y = 4 -------------(1)
x-y+3 = 0 --------------------(2)
Multiply equation (2) by 3.
⇒ 3x-3y+9 =0 ---------------(3)
Add equation (1) and equation (3)
2x+3y+3x-3y +9= 4
5x+9=4
5x=4-9
5x =-5
x=-1
Put x=-1 in Equation (1)
2(-1) +3y = 4
-2+3y =4
3y=4+2
3y = 6
y = 2
Therefore, x= -1 and y =2.
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