solve by elimination method,3(2x+y)=7xy,3(x+3y)=11xy
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Answered by
61
2x+y = 7xy/3
x+3y = 11xy/3 ⇒ 2x+6y = 22xy/3
5y = 5xy
x = 1
2x+y = 7xy/3 ⇒ 6x + 3y = 7xy
x+3y = 11xy/3
5x = 10xy/3
1 = 2y/3
y = 3/2
x+3y = 11xy/3 ⇒ 2x+6y = 22xy/3
5y = 5xy
x = 1
2x+y = 7xy/3 ⇒ 6x + 3y = 7xy
x+3y = 11xy/3
5x = 10xy/3
1 = 2y/3
y = 3/2
Anonymous:
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Answered by
12
6x+3y=7xy
3x+9y=11xy. =3x=11xy-9y
6x+3y=7xy
2(11xy-9y)+3y=7xy
22xy-18y+3y=7xy
15xy=15y
x=1
3x=11xy-9y
3×1=11×1×y-9y
3=11y-9y
y=3/2
I hope this will be helpful
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