Solve by elimination method
3a+5b=26;a+5b=22
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2
Answer:
Solution (a, b) =(2,4)
Step-by-step explanation:
3a+5b =26..................... (1)
a+5b=22....................... (2)
Subtracting equation (1) from (2)
3a+5b=26
a+5b=22
- -
2a. = 4
a= 4
2
a=2
Substituting in equation (1)
3(2)+5b=26
6+5b =26
5b=26-6
5b=20
b= 20
5
b=4
Solution (a, b) =(2,4)
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Answered by
1
Step-by-step explanation:
3a + 5b = 26; .....(I)
a + 5b = 22 .....(II)
Subtracting (II) from (I)
2a = 4
⇒ a = 2
Putting the value of a = 2 in (II)
5b = 22 - 2 = 20
⇒b = 20/5
=4
Thus, a = 2 and b = 4.
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