Question

Solve by elimination method:

3x-5y-4=0

9x=2y+7

please....URGENT!!

Answer 1

I hope this helps you.

Answer 2

Answer:

The solution is $(\frac{9}{13},-\frac{5}{13}$

Step-by-step explanation:

Given : $3x-5y-4=0$

           $9x=2y+7$

Solution:

$3x-5y=4$   -1

$9x-2y=7$    --2

Multiply equation 1 with 3 And then subtract it from 2

$3(3x-5y=4)$  

$9x-15y=12$

Now subtract it from 2

$9x-2y-9x+15y=7-12$

$13y=-5$

So, $y=-\frac{5}{13}$

Substitute y in 1 to get value of x

$3x-5(-\frac{5}{13})=4$

$3x+\frac{25}{13}=4$

$3x=4-\frac{25}{13}$

$3x=\frac{27}{13}$

$x=\frac{27}{39}$

$x=\frac{9}{13}$

Thus the solution is $(\frac{9}{13},-\frac{5}{13})$