Question

Solve by elimination method 3x-y=23,4x+3y=48 plz solve

Answer 1

Elimination Method:-

Given 2 Equations That:-

3x - y = 23 ------ (i)

4x + 3y = 48 ------ (ii)

consider equation (i)

3x - y = 23 x 3

= 9x - 3y = 69 ---------- (iii)

consider equation (ii) and (iii)

9x - 3y = 69

4x + 3y = 48

13x = 117

x = 117/13

Therefore, x = 9

Substitute x = 9 in (ii)

4x + 3y = 48

4(9) + 3y = 48

36 + 3y = 48

3y = 48 - 36

3y = 12

y = 12/3

Therefore, y = 4

therefore, x = 9 , y = 4

Answer 2

Answer:

X=9 , Y =4

Step-by-step explanation:

elimination method

given 2 equations that

3x-y = 23..........(1)

4x+3y= 48.........(2)

consider equation ........(1)

3x-y = 23×3

or,9x-3y =69 ............(3)

consider equation (2) and (3)

9x-3y = 69

4x+3y = 48

____________

13x = 117

or, x = 117/13

therefore, x=9

substitute, x=9 in (2)

4x+3y = 48

4(9)+3y= 48

36+3y =48

or, 3y = 48-36

or, 3y= 12

or, y= 4

therefore , x= 9 , y = 4

hope this will help you