solve by elimination method: 3x-y=7; 2x+5y+1=0
Answers
Answered by
131
Answer :
Here, the given equations are
3x - y = 7 ...(i)
2x + 5y = - 1 ...(ii)
Now, multiplying (i) by 5 and (ii) by (-1), we get
15x - 5y = 35
- 2x - 5y = 1
On subtraction, we get
17x = 34
⇒ x = 34/17
⇒ x = 2
Now, putting x = 2 in (i), we get
3 (2) - y = 7
⇒ 6 - y = 7
⇒ y = 6 - 7
⇒ y = - 1
Hence, the required solution be
x = 2 and y = - 1
#MarkAsBrainliest
Here, the given equations are
3x - y = 7 ...(i)
2x + 5y = - 1 ...(ii)
Now, multiplying (i) by 5 and (ii) by (-1), we get
15x - 5y = 35
- 2x - 5y = 1
On subtraction, we get
17x = 34
⇒ x = 34/17
⇒ x = 2
Now, putting x = 2 in (i), we get
3 (2) - y = 7
⇒ 6 - y = 7
⇒ y = 6 - 7
⇒ y = - 1
Hence, the required solution be
x = 2 and y = - 1
#MarkAsBrainliest
diyaa04113gmailcom:
that was easy
thanks a bunch
u did a great job
i know this method but wasn't able to solve this eqn
thanks once again
Answered by
7
Answer:
x=2 and y= -1
Step-by-step explanation:
multiplying 1st equation with -5
-5(3x-y=7) => -15+5y+35=0
on subtracting equation 2 from equation 1
(-15x-2x)+(5y-5y)+(35-1) => which gives us -17x+34=0
it means 34=17x
that means x= 34/17=2
x=2
on substituting value of x that is 2 in equation 1 (as your wish)
3*2-y=7
6-y=7
y=6-7
y=-1
so the answer is x=2 and y= -1
Similar questions