Solve by elimination method
4x+y/3=8/3
x/2+3y/4=-5/2
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Step-by-step explanation:
Hi ,
4x + y/3 = 8/3
multiply each term with 3 , we get
12x + y = 8
=> y = 8 - 12x ---( 1 )
x/2 + 3y/4 = -5/2----( 2 )
Substitute y = 8 - 12x in equation ( 2 ),
x/2 + ( 3/4 )[ 8 - 12x ] = -5/2
=> x/2 + 3[ 8/4 - 12x/4 ] = -5/2
=> x/2 + 3( 2 - 3x ) = -5/2
multiply each term with 2 , we get
=> x + 6( 2 - 3x ) = -5
=> x + 12 - 18x = -5
=> -17x = -5 - 12
=> -17x = -17
=> x = ( -17 )/( -17 )
x = 1
put x = 1 , in equation ( 1 ) , we get
y = 8 - 12 × 1
y = 8 - 12
y = -4
Therefore ,
x = 1 , y = -4
I hope this helps you.
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