solve by elimination method 55x+67x=311 ,67x+55x=299
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Given:
55x+67y=311
67x+55y=299
To find:
x and y by elimination method
Solution:
Let 55x+67y=311 be Equation 1
Let 67x+55y=299 be Equation 2
Multiply Equation 1 by 67
3685x + 4489y = 20837
Multiply Equation 2 by 55
3685x + 3025y = 16445
Solve Equation 1 and 2
3685x + 4489y = 20837
3685x + 3025y = 16445
(-) (-) (-)
1464y = 4392
y = 3
Subsitute value of y in Equation 1
55x + 67(3) = 311
55x = 110
x = 2
Hence, the value of x = 2 and y = 3.
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