Question

solve by elimination method
5x + 21y =0
7x + 3y = 0
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Answer 1

5x + 21y =0

7x + 3y = 0

5x + 21y =0

______________

(7x + 3y)7 = 0

=>>49x+21y=0

==>>

49x+21y=0

5x+21y=0 (subtracting)

____________

44x=0

x=0/44

x=0

_________________________________________

(5x + 21y)7 =0. (multiplying by 7 both sides)

35x+147y=0.........(1)

(7x + 3y)5= 0 {multiplying by 5 }

35x+15y=0......(2)

subtracting (2) from (1)

35x+147y=0

35x+15y =0

__________

132y=0

y=0/132

y=0

Answer 2

5x + 21y=0
-49x-21y=0 ( let us multiply by -7)
——————
-44x =0
x=0


Substitute x=0 in 5x+21y=0

5 x 0 + 21y = 0
y = 0


X = 0, Y = 0