Question

solve by elimination method 5x-2y=1
x+3y=1
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Answer 1

5x-2y=1------(1)

x+3y=1-------(2)

Multiplying by 5, in eq-(2)

5x -2y =1

5x +15y =5

- - -

___________

0 -17y = -4

minus(-) se minus(-) cancel ❌ ho jaega

y= 4/17

y= 4.25

Put the value of y= 4.25, in eq-(1)

5x -2y =1

5x -2(4.25) =1

5x -(8.50) =1

5x -8.50 =1

5x =1+8.50

5x = 9.50

x = 9.50/5

point hat jaega jitne digit ke baad point hai utne hi zero (0) niche aa jaenge ok!

x= 950/500

x= 19

The value of x= 19 and y= 4.25