Question

solve by elimination method. a) 2x -3y=7, 5x + y=9​

Answer 1

$\huge\tt\fcolorbox{red}{bl}{Answer}$

2x−3y=7 ----------------(1)

5x+y=9

y=9−5x-------------(2)

Now, substitute equation (2) in equation (1)

Then ,2x−3(9−5x)=7

2x−27+15x=7

17x=27+7

17x=34

x=34/17=2

y=9−5×2=9−10=−1

Therefore x is 2 and y is −1

Answer 2

$\huge\tt\fcolorbox{red}{bl}{Answer}$

2x−3y=7 ----------------(1)

5x+y=9

y=9−5x-------------(2)

Now, substitute equation (2) in equation (1)

Then ,2x−3(9−5x)=7

2x−27+15x=7

17x=27+7

17x=34

x=34/17=2

y=9−5×2=9−10=−1

Therefore x is 2 and y is −1