Question

Solve by elimination method s-t=3 s/3+t/2=6​

Answer 1

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$\sf Solve~by~elimination~method:\\\\\sf s-t=3 \\\\\sf \frac{s}{3}+\frac{t}{2}=6$

${\boxed{\underline{\purple{\bf\tt{Solution:} } }}}$

$\sf s-t=3-----(i) \\\\\sf \frac{s}{3}+\frac{t}{2}=6----(ii) \\\\\sf Multiplying~(ii)~by~2,~we~get: \\\\\sf \frac{2s}{3}+t=12----(iii) \\\\\sf Adding ~(i)~and~(iii), we~get: \\\\\sf \frac{2s}{3}+ s=15 \\\\\sf \frac{5s}{3}=15 \\\\\sf 5s=45 \\\\\sf \huge\boxed{s= 9}\\\\\sf \huge \underline{\: \:\: \: \:\: \: \:\: \: \:\: \: \:\: \: \:\: \: \:\: \: \:\: \: \:\: \: \:\: \: \:\: \: \:\: \: \:\: \: \:\: \: \:} \\\\\sf Putting~s=9~in~(i),\\\\\sf we~get~ 9-t=3~\\\\\sf \huge \boxed{t=6}$

Answer 2

s - t = 3 ------(i)

s/t + t/2 = 6 ----( ii)

(i) ⟹s = 3 + t ----( iii)

Now, substituting the value of s in equation ( ii)

3 + t + t/ 2 = 6

3

⟹ 6+2t+3t = 6

6

⟹ 6 + 5t= 6

6

⟹6 + 5t = 36

⟹5t = 30

⟹t = 6

Putting the value of t in equation (iii)

s = 3 + 6

= 9

∴ s = 9, t = 6