Question

solve by elimination method

x/2 + 2y/3= -1
x- y/3=3​

Answer 1

Step-by-step explanation:

Given:-

${\frac{x}{2}}+{\frac{2y}{3}}=-1$

$\implies{\frac{3x+4y}{3}}=-1$

$\implies{3x+4y=-3}----(1)$

${\frac{x-y}{3}}=3$

$\implies{x-y=9---(2)}$

Solution:

by multiplying 1 into eq (1) and 3 into eq (2) we get

${3x+4y=-3------(3)}$

$\underline{3x-3y=27}----(4)$

$\implies{7y=-30}$

$\implies{y={\frac{-30}{7}}}$

by putting the value of y into eq (2) we get

$x-{\frac{-30}{7}}=9$

$\implies{x=}{9+{\frac{7}{-30}}}$

$\implies{x={\frac {277}{-7}}}$

hence the solution is

${\boxed{x={\frac{277}{-30}},y={\frac{-30}{7}}}}$