solve by elimination method x+2y=7,x-2y=1
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Answered by
3
x+2y= 7......1
x-2y=1 ......2
![x + 2y = 1 \\ x - 2y = 1 \\ 2x = 8 \\ x = 4 x + 2y = 1 \\ x - 2y = 1 \\ 2x = 8 \\ x = 4](https://tex.z-dn.net/?f=x+%2B+2y+%3D+1+%5C%5C+x+-+2y+%3D+1+%5C%5C+2x+%3D+8+%5C%5C+x+%3D+4)
put x=4 in 1
![4 + 2y = 7 \\ 2y = 7 - 4 \\ 2y = 3 \\ y = 3/2 4 + 2y = 7 \\ 2y = 7 - 4 \\ 2y = 3 \\ y = 3/2](https://tex.z-dn.net/?f=4+%2B+2y+%3D+7+%5C%5C+2y+%3D+7+-+4+%5C%5C+2y+%3D+3+%5C%5C+y+%3D+3%2F2+)
Therefore (x,y) (4,3/2)
x-2y=1 ......2
put x=4 in 1
Therefore (x,y) (4,3/2)
Answered by
2
let X+2Y=7 be the equation one
and X-2Y=1 be the equation 2
X+2Y=7
X-2Y=1
_______
2X=8
X=4
and substitute x value in eq 1,we gwt
Y=3/2=1.5
and X-2Y=1 be the equation 2
X+2Y=7
X-2Y=1
_______
2X=8
X=4
and substitute x value in eq 1,we gwt
Y=3/2=1.5
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