solve by elimination method x-3y=3, 3x-9y=2
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The given system of equations is:
x − 3y – 3 = 0
3x − 9y − 2 = 0
The above equations are of the form
a1 x + b1 y − c1 = 0
a2 x + b2 y − c2 = 0
Here, a1 = 1, b1 = −3, c1 = −3
a2 = 3, b2 = −9, c2 = −2
So according to the question, we get
a1a2a1a2 = 1313
b1b2b1b2 = −3−9−3−9 = 1313 and,
c1c2c1c2 = −3−2−3−2 = 3232
⇒ a1a2a1a2 =b1b2b1b2 ≠ c1c2c1c2
Hence, we can conclude that the given system of equation has no solution.
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