Math, asked by itskajalpatel18, 4 months ago

solve by elimination method x-3y=3, 3x-9y=2​

Answers

Answered by Anonymous
1

Answer:

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Answered by nehabhosale454
23

Answer:

The given system of equations is:

x − 3y – 3 = 0

3x − 9y − 2 = 0

The above equations are of the form

a1 x + b1 y − c1 = 0

a2 x + b2 y − c2 = 0

Here, a1 = 1, b1 = −3, c1 = −3

a2 = 3, b2 = −9, c2 = −2

So according to the question, we get

a1a2a1a2 = 1313

b1b2b1b2 = −3−9−3−9 = 1313 and,

c1c2c1c2 = −3−2−3−2 = 3232

⇒ a1a2a1a2 =b1b2b1b2 ≠ c1c2c1c2

Hence, we can conclude that the given system of equation has no solution.

Step-by-step explanation:

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