solve by elimination method, x+y=5;2x-3y=5
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Answered by
52
Solution;
Given system of equations
are
x+y= 5 ---(1)
2x-3y=5 ---(2)
multiply (1) by 3 we get
3x+3y=15 ---(3)
Now , add (2) and (3) , we get
=> 5x = 20
=> x = 20/5
=> x = 4
substitute x = 4 in equation (1),
we get
4 + y = 5
=> y = 5-4
=> y = 1
Therefore,.
x = 4 , y = 1
••••
Answered by
39
Sorry for the scratches
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