solve by elininatis method 5m-5n=12,2m+9n=20
Answers
Answer:
5m-5n=12...eq1
2m+9n=20...eq2
Step-by-step explanation:
Now multiplying eq1 with 2
(5m-5n=12)×2
10m-10n=24...eq3
Now multiplying eq2 with 5
(2m+9n=20)×5
10m+45n=100...eq4
from eq3 and eq4,we obtained
10m+45n=100
- ( 10m-10n=24)
so ,
10m+45n= 100
- 10m+10n= -24
.: 0+55n= 76
n=76/55
putting n=76/55 in eq1
5m-5n=12
5m-5(76/55)=12
5m-76/11=12
( 55m-76)÷11=12
( 55m-76)=12×11
55m-76=132
55m=132+76
55m=208
m=208/55
therefore,
n=76/55
m=208/55
Answer:
5m-5n=12.......(1)
2m+9n=20......(2)
from eq.(1)
5m-5n=12
5m=12+5n
m=12+5n/5...... (3)
Now,
By putting the value of m in eq. ( 2 )
2m+9n=20
2 (12+5n/5)+ 9n=20
24+10n/5+9n=20
24+10n+45n/5=20
24+55n=100
55n=100-24
55n=76
now putting the value of n in eq. ( 3 )
m=12+5n/5
m=12+76/55/5
m=660+76/55/5
m=736/55×1/5
m=736/275